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Serie: Commander 2018 (C18)
Serie | Normaal | Foil | ||
Commander 2018 | 1,00 |
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Ik had afgelopen zondag een magnifieke play met deze dame.
Panharmonicon & Aminatou, the Fateshifter in play en een Magister Sphinx on top. Ik val aan met Yennett, Cryptic Sovereign en reveal Magister Sphinx, deze entered the battlefield en haar ability triggered twee keer dankzij Panharmonicon. Na combat blink ik Magister Sphinx met Aminatou, the Fateshifter waardoor haar ability nóg twee keer triggeren. In één beurt vier tegenstanders op 10 leven gezet
Maar..
De beurt erop steelt iemand mijn Magister Sphinx en kopieert deze d.m.v. een Kiki-Jiki, Mirror Breaker en zet mij op 10 leven. What goes around, comes around.
I <3 Commander
Legendary Creature - Sphinx 3 / 5
Flying, vigilance, menace
Whenever Yennett, Cryptic Sovereign attacks, reveal the top card of your library. If that card's converted mana cost is odd, you may cast it without paying its mana cost. Otherwise, draw a card.
Legal in: Vintage, Legacy, Commander
7/13/2018
If the revealed card doesn’t have an odd converted mana cost or if that card does but you choose not to cast it, you draw a card. Keep in mind that revealing a card doesn’t cause it to change zones. This means that the card you draw will be the card you revealed.
7/13/2018
If you cast a card “without paying its mana cost,” you can’t choose to cast it for any alternative costs, such as evoke costs. You can, however, pay additional costs. If the card has any mandatory additional costs, such as that of Tormenting Voice, those must be paid to cast it.
7/13/2018
If a spell has X in its mana cost, you must choose 0 as the value of X if you cast it without paying its mana cost.
7/13/2018
If you wish to cast the revealed card without paying its mana cost, you must cast it while Yennett’s triggered ability is resolving; you can’t cast for free it later in the turn.
7/13/2018
Because all attackers are chosen at once, a spell cast this way can’t affect which creatures you can attack with, but it can affect which creatures will be able to block.
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